55=(t^2-t)/2

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Solution for 55=(t^2-t)/2 equation: 


t in (-oo:+oo)

55 = (t^2-t)/2 // - (t^2-t)/2

55-((t^2-t)/2) = 0

(-1*(t^2-t))/2+55 = 0

(-1*(t^2-t))/2+(2*55)/2 = 0

2*55-1*(t^2-t) = 0

t-t^2+110 = 0

t-t^2+110 = 0

t-t^2+110 = 0

DELTA = 1^2-(-1*4*110)

DELTA = 441

DELTA > 0

t = (441^(1/2)-1)/(-1*2) or t = (-441^(1/2)-1)/(-1*2)

t = -10 or t = 11

(t+10)*(t-11) = 0

((t+10)*(t-11))/2 = 0

((t+10)*(t-11))/2 = 0 // * 2

(t+10)*(t-11) = 0

( t+10 )

t+10 = 0 // - 10

t = -10

( t-11 )

t-11 = 0 // + 11

t = 11

t in { -10, 11 }

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